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86x=12x^2+14
We move all terms to the left:
86x-(12x^2+14)=0
We get rid of parentheses
-12x^2+86x-14=0
a = -12; b = 86; c = -14;
Δ = b2-4ac
Δ = 862-4·(-12)·(-14)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-82}{2*-12}=\frac{-168}{-24} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+82}{2*-12}=\frac{-4}{-24} =1/6 $
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